Metadata-Version: 2.1
Name: wordhunt-anagram-search-python
Version: 0.1.2
Summary: A python client library for word search in games like iMessage wordhunt and anagram.
Home-page: https://github.com/bstudiosoriginal/WordHuntAnagram
Author: Immanuel Adotey Allotey
Author-email: imma.adt@gmail.com
License: UNKNOWN
Keywords: word games,word search,anagram,wordhunt,iMessage games
Platform: UNKNOWN
Classifier: Development Status :: 3 - Alpha
Classifier: Intended Audience :: End Users/Desktop
Classifier: License :: OSI Approved :: MIT License
Classifier: Natural Language :: English
Classifier: Operating System :: OS Independent
Classifier: Programming Language :: Python :: 3 :: Only
Classifier: Programming Language :: Python :: 3.5
Classifier: Programming Language :: Python :: 3.6
Classifier: Programming Language :: Python :: 3.7
Classifier: Programming Language :: Python :: 3.8
Classifier: Programming Language :: Python :: 3.9
Requires-Python: >=3.5
Description-Content-Type: text/markdown

# WordHuntAnagram
 Play iMessage Anagram and wordhunt or any search word game using this `module`.

# Example

`

    from wordhuntanagram.wordhunt import WordHunt

    word = WordHunt(4, 4, args='yiuonhjnhffhggdb', auto_input=False)
    word.hunt()
    print(word.words)

`

`

    from wordhuntanagram.anagram import Anagram

    anagram = Anagram(args='ioijbf', auto_input=False)
    anagram.hunt()
    print(anagram.words)

`

---
Note that you have to be quick in doing all this. Its advisable to use a while loop.

---

`

    run = True
    while run:
        type_ = input("Choose type: (wordhunt-w/anagram-a)")
        if type_ == 'w' or type_ == 'wordhunt':
            word = WordHunt(4, 4)
            word.hunt()
            for item in word.words:
                print(item, '', word.words[item])
        elif type_ == 'a' or type_ == 'anagram':
            anagram = Anagram(6)
            anagram.hunt()
            for item in word.words:
                print(item, '', word.words[item])
        else:
            print("Input valid type")
        continuation = input("Press y to continue, any key to exit")
        if continuation != 'y':
            run = False
        else:
            ### you can clear the terminal here
            pass

`

**Enjoy!**

