/*! @file slamch.c
 * \brief Determines single precision machine parameters and other service routines
 *
 * <pre>
 *   -- LAPACK auxiliary routine (version 2.0) --   
 *      Univ. of Tennessee, Univ. of California Berkeley, NAG Ltd.,   
 *      Courant Institute, Argonne National Lab, and Rice University   
 *      October 31, 1992   
 * </pre>
 */
#include <stdio.h>
#include "slu_Cnames.h"

#define TRUE_ (1)
#define FALSE_ (0)
#define min(a,b) ((a) <= (b) ? (a) : (b))
#define max(a,b) ((a) >= (b) ? (a) : (b))
#define abs(x) ((x) >= 0 ? (x) : -(x))
#define dabs(x) (double)abs(x)

/*! \brief

<pre>
 Purpose   
    =======   

    SLAMCH determines single precision machine parameters.   

    Arguments   
    =========   

    CMACH   (input) CHARACTER*1   
            Specifies the value to be returned by SLAMCH:   
            = 'E' or 'e',   SLAMCH := eps   
            = 'S' or 's ,   SLAMCH := sfmin   
            = 'B' or 'b',   SLAMCH := base   
            = 'P' or 'p',   SLAMCH := eps*base   
            = 'N' or 'n',   SLAMCH := t   
            = 'R' or 'r',   SLAMCH := rnd   
            = 'M' or 'm',   SLAMCH := emin   
            = 'U' or 'u',   SLAMCH := rmin   
            = 'L' or 'l',   SLAMCH := emax   
            = 'O' or 'o',   SLAMCH := rmax   

            where   

            eps   = relative machine precision   
            sfmin = safe minimum, such that 1/sfmin does not overflow   
            base  = base of the machine   
            prec  = eps*base   
            t     = number of (base) digits in the mantissa   
            rnd   = 1.0 when rounding occurs in addition, 0.0 otherwise   
            emin  = minimum exponent before (gradual) underflow   
            rmin  = underflow threshold - base**(emin-1)   
            emax  = largest exponent before overflow   
            rmax  = overflow threshold  - (base**emax)*(1-eps)   

   ===================================================================== 
</pre>
*/
float slamch_(char *cmach)
{
/* >>Start of File<<   
       Initialized data */
    static int first = TRUE_;
    /* System generated locals */
    int i__1;
    float ret_val;
    /* Builtin functions */
    double pow_ri(float *, int *);
    /* Local variables */
    static float base;
    static int beta;
    static float emin, prec, emax;
    static int imin, imax;
    static int lrnd;
    static float rmin, rmax, t, rmach;
    extern int lsame_(char *, char *);
    static float small, sfmin;
    extern /* Subroutine */ int slamc2_(int *, int *, int *, float 
	    *, int *, float *, int *, float *);
    static int it;
    static float rnd, eps;



    if (first) {
	first = FALSE_;
	slamc2_(&beta, &it, &lrnd, &eps, &imin, &rmin, &imax, &rmax);
	base = (float) beta;
	t = (float) it;
	if (lrnd) {
	    rnd = 1.f;
	    i__1 = 1 - it;
	    eps = pow_ri(&base, &i__1) / 2;
	} else {
	    rnd = 0.f;
	    i__1 = 1 - it;
	    eps = pow_ri(&base, &i__1);
	}
	prec = eps * base;
	emin = (float) imin;
	emax = (float) imax;
	sfmin = rmin;
	small = 1.f / rmax;
	if (small >= sfmin) {

/*           Use SMALL plus a bit, to avoid the possibility of rou
nding   
             causing overflow when computing  1/sfmin. */

	    sfmin = small * (eps + 1.f);
	}
    }

    if (lsame_(cmach, "E")) {
	rmach = eps;
    } else if (lsame_(cmach, "S")) {
	rmach = sfmin;
    } else if (lsame_(cmach, "B")) {
	rmach = base;
    } else if (lsame_(cmach, "P")) {
	rmach = prec;
    } else if (lsame_(cmach, "N")) {
	rmach = t;
    } else if (lsame_(cmach, "R")) {
	rmach = rnd;
    } else if (lsame_(cmach, "M")) {
	rmach = emin;
    } else if (lsame_(cmach, "U")) {
	rmach = rmin;
    } else if (lsame_(cmach, "L")) {
	rmach = emax;
    } else if (lsame_(cmach, "O")) {
	rmach = rmax;
    }

    ret_val = rmach;
    return ret_val;

/*     End of SLAMCH */

} /* slamch_ */


/* Subroutine */ 
/*! \brief

<pre>
 Purpose   
    =======   

    SLAMC1 determines the machine parameters given by BETA, T, RND, and   
    IEEE1.   

    Arguments   
    =========   

    BETA    (output) INT   
            The base of the machine.   

    T       (output) INT   
            The number of ( BETA ) digits in the mantissa.   

    RND     (output) INT   
            Specifies whether proper rounding  ( RND = .TRUE. )  or   
            chopping  ( RND = .FALSE. )  occurs in addition. This may not 
  
            be a reliable guide to the way in which the machine performs 
  
            its arithmetic.   

    IEEE1   (output) INT   
            Specifies whether rounding appears to be done in the IEEE   
            'round to nearest' style.   

    Further Details   
    ===============   

    The routine is based on the routine  ENVRON  by Malcolm and   
    incorporates suggestions by Gentleman and Marovich. See   

       Malcolm M. A. (1972) Algorithms to reveal properties of   
          floating-point arithmetic. Comms. of the ACM, 15, 949-951.   

       Gentleman W. M. and Marovich S. B. (1974) More on algorithms   
          that reveal properties of floating point arithmetic units.   
          Comms. of the ACM, 17, 276-277.   

   ===================================================================== 
</pre>
*/

int slamc1_(int *beta, int *t, int *rnd, int 
	*ieee1)
{
    /* Initialized data */
    static int first = TRUE_;
    /* System generated locals */
    float r__1, r__2;
    /* Local variables */
    static int lrnd;
    static float a, b, c, f;
    static int lbeta;
    static float savec;
    static int lieee1;
    static float t1, t2;
    extern double slamc3_(float *, float *);
    static int lt;
    static float one, qtr;



    if (first) {
	first = FALSE_;
	one = 1.f;

/*        LBETA,  LIEEE1,  LT and  LRND  are the  local values  of  BE
TA,   
          IEEE1, T and RND.   

          Throughout this routine  we use the function  SLAMC3  to ens
ure   
          that relevant values are  stored and not held in registers, 
 or   
          are not affected by optimizers.   

          Compute  a = 2.0**m  with the  smallest positive integer m s
uch   
          that   

             fl( a + 1.0 ) = a. */

	a = 1.f;
	c = 1.f;

/* +       WHILE( C.EQ.ONE )LOOP */
L10:
	if (c == one) {
	    a *= 2;
	    c = slamc3_(&a, &one);
	    r__1 = -(double)a;
	    c = slamc3_(&c, &r__1);
	    goto L10;
	}
/* +       END WHILE   

          Now compute  b = 2.0**m  with the smallest positive integer 
m   
          such that   

             fl( a + b ) .gt. a. */

	b = 1.f;
	c = slamc3_(&a, &b);

/* +       WHILE( C.EQ.A )LOOP */
L20:
	if (c == a) {
	    b *= 2;
	    c = slamc3_(&a, &b);
	    goto L20;
	}
/* +       END WHILE   

          Now compute the base.  a and c  are neighbouring floating po
int   
          numbers  in the  interval  ( beta**t, beta**( t + 1 ) )  and
 so   
          their difference is beta. Adding 0.25 to c is to ensure that
 it   
          is truncated to beta and not ( beta - 1 ). */

	qtr = one / 4;
	savec = c;
	r__1 = -(double)a;
	c = slamc3_(&c, &r__1);
	lbeta = c + qtr;

/*        Now determine whether rounding or chopping occurs,  by addin
g a   
          bit  less  than  beta/2  and a  bit  more  than  beta/2  to 
 a. */

	b = (float) lbeta;
	r__1 = b / 2;
	r__2 = -(double)b / 100;
	f = slamc3_(&r__1, &r__2);
	c = slamc3_(&f, &a);
	if (c == a) {
	    lrnd = TRUE_;
	} else {
	    lrnd = FALSE_;
	}
	r__1 = b / 2;
	r__2 = b / 100;
	f = slamc3_(&r__1, &r__2);
	c = slamc3_(&f, &a);
	if (lrnd && c == a) {
	    lrnd = FALSE_;
	}

/*        Try and decide whether rounding is done in the  IEEE  'round
 to   
          nearest' style. B/2 is half a unit in the last place of the 
two   
          numbers A and SAVEC. Furthermore, A is even, i.e. has last  
bit   
          zero, and SAVEC is odd. Thus adding B/2 to A should not  cha
nge   
          A, but adding B/2 to SAVEC should change SAVEC. */

	r__1 = b / 2;
	t1 = slamc3_(&r__1, &a);
	r__1 = b / 2;
	t2 = slamc3_(&r__1, &savec);
	lieee1 = t1 == a && t2 > savec && lrnd;

/*        Now find  the  mantissa, t.  It should  be the  integer part
 of   
          log to the base beta of a,  however it is safer to determine
  t   
          by powering.  So we find t as the smallest positive integer 
for   
          which   

             fl( beta**t + 1.0 ) = 1.0. */

	lt = 0;
	a = 1.f;
	c = 1.f;

/* +       WHILE( C.EQ.ONE )LOOP */
L30:
	if (c == one) {
	    ++lt;
	    a *= lbeta;
	    c = slamc3_(&a, &one);
	    r__1 = -(double)a;
	    c = slamc3_(&c, &r__1);
	    goto L30;
	}
/* +       END WHILE */

    }

    *beta = lbeta;
    *t = lt;
    *rnd = lrnd;
    *ieee1 = lieee1;
    return 0;

/*     End of SLAMC1 */

} /* slamc1_ */


/* Subroutine */ 

/*! \brief

<pre>
    Purpose   
    =======   

    SLAMC2 determines the machine parameters specified in its argument   
    list.   

    Arguments   
    =========   

    BETA    (output) INT   
            The base of the machine.   

    T       (output) INT   
            The number of ( BETA ) digits in the mantissa.   

    RND     (output) INT   
            Specifies whether proper rounding  ( RND = .TRUE. )  or   
            chopping  ( RND = .FALSE. )  occurs in addition. This may not 
  
            be a reliable guide to the way in which the machine performs 
  
            its arithmetic.   

    EPS     (output) FLOAT   
            The smallest positive number such that   

               fl( 1.0 - EPS ) .LT. 1.0,   

            where fl denotes the computed value.   

    EMIN    (output) INT   
            The minimum exponent before (gradual) underflow occurs.   

    RMIN    (output) FLOAT   
            The smallest normalized number for the machine, given by   
            BASE**( EMIN - 1 ), where  BASE  is the floating point value 
  
            of BETA.   

    EMAX    (output) INT   
            The maximum exponent before overflow occurs.   

    RMAX    (output) FLOAT   
            The largest positive number for the machine, given by   
            BASE**EMAX * ( 1 - EPS ), where  BASE  is the floating point 
  
            value of BETA.   

    Further Details   
    ===============   

    The computation of  EPS  is based on a routine PARANOIA by   
    W. Kahan of the University of California at Berkeley.   

   ===================================================================== 
</pre>
*/
int slamc2_(int *beta, int *t, int *rnd, float *
	eps, int *emin, float *rmin, int *emax, float *rmax)
{
    /* Table of constant values */
    static int c__1 = 1;
    
    /* Initialized data */
    static int first = TRUE_;
    static int iwarn = FALSE_;
    /* System generated locals */
    int i__1;
    float r__1, r__2, r__3, r__4, r__5;
    /* Builtin functions */
    double pow_ri(float *, int *);
    /* Local variables */
    static int ieee;
    static float half;
    static int lrnd;
    static float leps, zero, a, b, c;
    static int i, lbeta;
    static float rbase;
    static int lemin, lemax, gnmin;
    static float small;
    static int gpmin;
    static float third, lrmin, lrmax, sixth;
    static int lieee1;
    extern /* Subroutine */ int slamc1_(int *, int *, int *, 
	    int *);
    extern double slamc3_(float *, float *);
    extern /* Subroutine */ int slamc4_(int *, float *, int *), 
	    slamc5_(int *, int *, int *, int *, int *, 
	    float *);
    static int lt, ngnmin, ngpmin;
    static float one, two;



    if (first) {
	first = FALSE_;
	zero = 0.f;
	one = 1.f;
	two = 2.f;

/*        LBETA, LT, LRND, LEPS, LEMIN and LRMIN  are the local values
 of   
          BETA, T, RND, EPS, EMIN and RMIN.   

          Throughout this routine  we use the function  SLAMC3  to ens
ure   
          that relevant values are stored  and not held in registers, 
 or   
          are not affected by optimizers.   

          SLAMC1 returns the parameters  LBETA, LT, LRND and LIEEE1. 
*/

	slamc1_(&lbeta, &lt, &lrnd, &lieee1);

/*        Start to find EPS. */

	b = (float) lbeta;
	i__1 = -lt;
	a = pow_ri(&b, &i__1);
	leps = a;

/*        Try some tricks to see whether or not this is the correct  E
PS. */

	b = two / 3;
	half = one / 2;
	r__1 = -(double)half;
	sixth = slamc3_(&b, &r__1);
	third = slamc3_(&sixth, &sixth);
	r__1 = -(double)half;
	b = slamc3_(&third, &r__1);
	b = slamc3_(&b, &sixth);
	b = dabs(b);
	if (b < leps) {
	    b = leps;
	}

	leps = 1.f;

/* +       WHILE( ( LEPS.GT.B ).AND.( B.GT.ZERO ) )LOOP */
L10:
	if (leps > b && b > zero) {
	    leps = b;
	    r__1 = half * leps;
/* Computing 5th power */
	    r__3 = two, r__4 = r__3, r__3 *= r__3;
/* Computing 2nd power */
	    r__5 = leps;
	    r__2 = r__4 * (r__3 * r__3) * (r__5 * r__5);
	    c = slamc3_(&r__1, &r__2);
	    r__1 = -(double)c;
	    c = slamc3_(&half, &r__1);
	    b = slamc3_(&half, &c);
	    r__1 = -(double)b;
	    c = slamc3_(&half, &r__1);
	    b = slamc3_(&half, &c);
	    goto L10;
	}
/* +       END WHILE */

	if (a < leps) {
	    leps = a;
	}

/*        Computation of EPS complete.   

          Now find  EMIN.  Let A = + or - 1, and + or - (1 + BASE**(-3
)).   
          Keep dividing  A by BETA until (gradual) underflow occurs. T
his   
          is detected when we cannot recover the previous A. */

	rbase = one / lbeta;
	small = one;
	for (i = 1; i <= 3; ++i) {
	    r__1 = small * rbase;
	    small = slamc3_(&r__1, &zero);
/* L20: */
	}
	a = slamc3_(&one, &small);
	slamc4_(&ngpmin, &one, &lbeta);
	r__1 = -(double)one;
	slamc4_(&ngnmin, &r__1, &lbeta);
	slamc4_(&gpmin, &a, &lbeta);
	r__1 = -(double)a;
	slamc4_(&gnmin, &r__1, &lbeta);
	ieee = FALSE_;

	if (ngpmin == ngnmin && gpmin == gnmin) {
	    if (ngpmin == gpmin) {
		lemin = ngpmin;
/*            ( Non twos-complement machines, no gradual under
flow;   
                e.g.,  VAX ) */
	    } else if (gpmin - ngpmin == 3) {
		lemin = ngpmin - 1 + lt;
		ieee = TRUE_;
/*            ( Non twos-complement machines, with gradual und
erflow;   
                e.g., IEEE standard followers ) */
	    } else {
		lemin = min(ngpmin,gpmin);
/*            ( A guess; no known machine ) */
		iwarn = TRUE_;
	    }

	} else if (ngpmin == gpmin && ngnmin == gnmin) {
	    if ((i__1 = ngpmin - ngnmin, abs(i__1)) == 1) {
		lemin = max(ngpmin,ngnmin);
/*            ( Twos-complement machines, no gradual underflow
;   
                e.g., CYBER 205 ) */
	    } else {
		lemin = min(ngpmin,ngnmin);
/*            ( A guess; no known machine ) */
		iwarn = TRUE_;
	    }

	} else if ((i__1 = ngpmin - ngnmin, abs(i__1)) == 1 && gpmin == gnmin)
		 {
	    if (gpmin - min(ngpmin,ngnmin) == 3) {
		lemin = max(ngpmin,ngnmin) - 1 + lt;
/*            ( Twos-complement machines with gradual underflo
w;   
                no known machine ) */
	    } else {
		lemin = min(ngpmin,ngnmin);
/*            ( A guess; no known machine ) */
		iwarn = TRUE_;
	    }

	} else {
/* Computing MIN */
	    i__1 = min(ngpmin,ngnmin), i__1 = min(i__1,gpmin);
	    lemin = min(i__1,gnmin);
/*         ( A guess; no known machine ) */
	    iwarn = TRUE_;
	}
/* **   
   Comment out this if block if EMIN is ok */
	if (iwarn) {
	    first = TRUE_;
	    printf("\n\n WARNING. The value EMIN may be incorrect:- ");
	    printf("EMIN = %8i\n",lemin);
	    printf("If, after inspection, the value EMIN looks acceptable");
            printf("please comment out \n the IF block as marked within the"); 
            printf("code of routine SLAMC2, \n otherwise supply EMIN"); 
            printf("explicitly.\n");
	}
/* **   

          Assume IEEE arithmetic if we found denormalised  numbers abo
ve,   
          or if arithmetic seems to round in the  IEEE style,  determi
ned   
          in routine SLAMC1. A true IEEE machine should have both  thi
ngs   
          true; however, faulty machines may have one or the other. */

	ieee = ieee || lieee1;

/*        Compute  RMIN by successive division by  BETA. We could comp
ute   
          RMIN as BASE**( EMIN - 1 ),  but some machines underflow dur
ing   
          this computation. */

	lrmin = 1.f;
	i__1 = 1 - lemin;
	for (i = 1; i <= 1-lemin; ++i) {
	    r__1 = lrmin * rbase;
	    lrmin = slamc3_(&r__1, &zero);
/* L30: */
	}

/*        Finally, call SLAMC5 to compute EMAX and RMAX. */

	slamc5_(&lbeta, &lt, &lemin, &ieee, &lemax, &lrmax);
    }

    *beta = lbeta;
    *t = lt;
    *rnd = lrnd;
    *eps = leps;
    *emin = lemin;
    *rmin = lrmin;
    *emax = lemax;
    *rmax = lrmax;

    return 0;


/*     End of SLAMC2 */

} /* slamc2_ */

/*! \brief

<pre>
    Purpose   
    =======   

    SLAMC3  is intended to force  A  and  B  to be stored prior to doing 
  
    the addition of  A  and  B ,  for use in situations where optimizers 
  
    might hold one of these in a register.   

    Arguments   
    =========   

    A, B    (input) FLOAT   
            The values A and B.   

   ===================================================================== 
</pre>
*/

double slamc3_(float *a, float *b)
{

/* >>Start of File<<   
       System generated locals */
    volatile float ret_val;
    volatile float x;
    volatile float y;

    x = *a;
    y = *b;
    ret_val = x + y;

    return ret_val;

/*     End of SLAMC3 */

} /* slamc3_ */


/* Subroutine */ 

/*! \brief

<pre>
    Purpose   
    =======   

    SLAMC4 is a service routine for SLAMC2.   

    Arguments   
    =========   

    EMIN    (output) EMIN   
            The minimum exponent before (gradual) underflow, computed by 
  
            setting A = START and dividing by BASE until the previous A   
            can not be recovered.   

    START   (input) FLOAT   
            The starting point for determining EMIN.   

    BASE    (input) INT   
            The base of the machine.   

   ===================================================================== 
</pre>
*/

int slamc4_(int *emin, float *start, int *base)
{
    /* System generated locals */
    int i__1;
    float r__1;
    /* Local variables */
    static float zero, a;
    static int i;
    static float rbase, b1, b2, c1, c2, d1, d2;
    extern double slamc3_(float *, float *);
    static float one;



    a = *start;
    one = 1.f;
    rbase = one / *base;
    zero = 0.f;
    *emin = 1;
    r__1 = a * rbase;
    b1 = slamc3_(&r__1, &zero);
    c1 = a;
    c2 = a;
    d1 = a;
    d2 = a;
/* +    WHILE( ( C1.EQ.A ).AND.( C2.EQ.A ).AND.   
      $       ( D1.EQ.A ).AND.( D2.EQ.A )      )LOOP */
L10:
    if (c1 == a && c2 == a && d1 == a && d2 == a) {
	--(*emin);
	a = b1;
	r__1 = a / *base;
	b1 = slamc3_(&r__1, &zero);
	r__1 = b1 * *base;
	c1 = slamc3_(&r__1, &zero);
	d1 = zero;
	i__1 = *base;
	for (i = 1; i <= *base; ++i) {
	    d1 += b1;
/* L20: */
	}
	r__1 = a * rbase;
	b2 = slamc3_(&r__1, &zero);
	r__1 = b2 / rbase;
	c2 = slamc3_(&r__1, &zero);
	d2 = zero;
	i__1 = *base;
	for (i = 1; i <= *base; ++i) {
	    d2 += b2;
/* L30: */
	}
	goto L10;
    }
/* +    END WHILE */

    return 0;

/*     End of SLAMC4 */

} /* slamc4_ */


/* Subroutine */ 
/*! \brief

<pre>
    Purpose   
    =======   

    SLAMC5 attempts to compute RMAX, the largest machine floating-point   
    number, without overflow.  It assumes that EMAX + abs(EMIN) sum   
    approximately to a power of 2.  It will fail on machines where this   
    assumption does not hold, for example, the Cyber 205 (EMIN = -28625, 
  
    EMAX = 28718).  It will also fail if the value supplied for EMIN is   
    too large (i.e. too close to zero), probably with overflow.   

    Arguments   
    =========   

    BETA    (input) INT   
            The base of floating-point arithmetic.   

    P       (input) INT   
            The number of base BETA digits in the mantissa of a   
            floating-point value.   

    EMIN    (input) INT   
            The minimum exponent before (gradual) underflow.   

    IEEE    (input) INT   
            A logical flag specifying whether or not the arithmetic   
            system is thought to comply with the IEEE standard.   

    EMAX    (output) INT   
            The largest exponent before overflow   

    RMAX    (output) FLOAT   
            The largest machine floating-point number.   

   ===================================================================== 
  


       First compute LEXP and UEXP, two powers of 2 that bound   
       abs(EMIN). We then assume that EMAX + abs(EMIN) will sum   
       approximately to the bound that is closest to abs(EMIN).   
       (EMAX is the exponent of the required number RMAX). 
</pre>
*/

int slamc5_(int *beta, int *p, int *emin, 
	int *ieee, int *emax, float *rmax)
{
    /* Table of constant values */
    static float c_b5 = 0.f;
    
    /* System generated locals */
    int i__1;
    float r__1;
    /* Local variables */
    static int lexp;
    static float oldy;
    static int uexp, i;
    static float y, z;
    static int nbits;
    extern double slamc3_(float *, float *);
    static float recbas;
    static int exbits, expsum, try__;



    lexp = 1;
    exbits = 1;
L10:
    try__ = lexp << 1;
    if (try__ <= -(*emin)) {
	lexp = try__;
	++exbits;
	goto L10;
    }
    if (lexp == -(*emin)) {
	uexp = lexp;
    } else {
	uexp = try__;
	++exbits;
    }

/*     Now -LEXP is less than or equal to EMIN, and -UEXP is greater   
       than or equal to EMIN. EXBITS is the number of bits needed to   
       store the exponent. */

    if (uexp + *emin > -lexp - *emin) {
	expsum = lexp << 1;
    } else {
	expsum = uexp << 1;
    }

/*     EXPSUM is the exponent range, approximately equal to   
       EMAX - EMIN + 1 . */

    *emax = expsum + *emin - 1;
    nbits = exbits + 1 + *p;

/*     NBITS is the total number of bits needed to store a   
       floating-point number. */

    if (nbits % 2 == 1 && *beta == 2) {

/*        Either there are an odd number of bits used to store a   
          floating-point number, which is unlikely, or some bits are 
  
          not used in the representation of numbers, which is possible
,   
          (e.g. Cray machines) or the mantissa has an implicit bit,   
          (e.g. IEEE machines, Dec Vax machines), which is perhaps the
   
          most likely. We have to assume the last alternative.   
          If this is true, then we need to reduce EMAX by one because 
  
          there must be some way of representing zero in an implicit-b
it   
          system. On machines like Cray, we are reducing EMAX by one 
  
          unnecessarily. */

	--(*emax);
    }

    if (*ieee) {

/*        Assume we are on an IEEE machine which reserves one exponent
   
          for infinity and NaN. */

	--(*emax);
    }

/*     Now create RMAX, the largest machine number, which should   
       be equal to (1.0 - BETA**(-P)) * BETA**EMAX .   

       First compute 1.0 - BETA**(-P), being careful that the   
       result is less than 1.0 . */

    recbas = 1.f / *beta;
    z = *beta - 1.f;
    y = 0.f;
    i__1 = *p;
    for (i = 1; i <= *p; ++i) {
	z *= recbas;
	if (y < 1.f) {
	    oldy = y;
	}
	y = slamc3_(&y, &z);
/* L20: */
    }
    if (y >= 1.f) {
	y = oldy;
    }

/*     Now multiply by BETA**EMAX to get RMAX. */

    i__1 = *emax;
    for (i = 1; i <= *emax; ++i) {
	r__1 = y * *beta;
	y = slamc3_(&r__1, &c_b5);
/* L30: */
    }

    *rmax = y;
    return 0;

/*     End of SLAMC5 */

} /* slamc5_ */


double pow_ri(float *ap, int *bp)
{
double pow, x;
int n;

pow = 1;
x = *ap;
n = *bp;

if(n != 0)
	{
	if(n < 0)
		{
		n = -n;
		x = 1/x;
		}
	for( ; ; )
		{
		if(n & 01)
			pow *= x;
		if(n >>= 1)
			x *= x;
		else
			break;
		}
	}
return(pow);
}
