# Mutation from 'input.py'
import os
import sys
from typing import Any, Callable, Dict, List, Optional, Tuple

import numpy as np

import geniz


@geniz.CodeAgent()
def make_palindrome(s: str) -> str:
    """
    Transforms a given string into the shortest palindrome beginning with it.
    
    Algorithm Explanation:
    - Finds the longest palindromic suffix within the given string.
    - Attaches the reverse of the prefix preceding the palindromic suffix at the end, effectively 
      creating a palindrome that starts with the original string.
    
    The function efficiently works in O(n^2) time complexity due to the process to find the longest 
    palindromic suffix within the string. However, it optimally satisfies the problem statement.
    
    Parameters:
    s (str): The input string we transform into the specified palindrome format.
    
    Returns:
    str: The transformed string that is a palindrome resembling the original string with its mirrored portion at the end.
    
    Examples:
    >>> make_palindrome('')
    ''
    >>> make_palindrome('cat')
    'catac'
    >>> make_palindrome('blackcarrot')
    'blackcarrototcarbalc'
    """
    if not s:
        return ''
    is_palindrome = lambda x: x == x[::-1]
    for i in range(len(s) - 1, -1, -1):
        if is_palindrome(s[i:]):
            return s + s[:i][::-1]
if __name__ == '__main__':
    assert make_palindrome('abcd') == 'abcdcba'
    print('All test cases pass')
