LLT(3f)

DESCRIPTION
Determines whether one string is lexically less than another string, where the two strings are interpreted as containing ASCII character codes. If the String A and String B are not the same length, the shorter is compared as if spaces were appended to it to form a value that has the same length as the longer.

In general, the lexical comparison intrinsics LGE, LGT, LLE, and LLT differ from the corresponding intrinsic operators .GE., .GT., .LE., and .LT., in that the latter use the processor's character ordering (which is not ASCII on some targets), whereas the former always use the ASCII ordering.

STANDARD
Fortran 77 and later

CLASS
Elemental function

SYNTAX
RESULT = LLT(STRING_A, STRING_B)

ARGUMENTS

STRING_A Shall be of default CHARACTER type. STRING_B Shall be of default CHARACTER type.

RETURN VALUE
Returns .TRUE. if STRING_A < STRING_B, and .FALSE. otherwise, based on the ASCII ordering.

SPECIFIC NAMES

Name Argument Return type Standard LLT(STRING_A, STRING_B) CHARACTER LOGICAL Fortran 77 and later

SEE ALSO
LGE, LGT, LLE

AUTHOR

This information was taken from the GFortran documentation (https://gcc.gnu.org/onlinedocs/gcc-5.3.0/gfortran/) and converted to a manpage by AstroFloyd (http://astrofloyd.org).